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.Q:

Why do we convert $\sin 60^o$ into $\sin(60^o+45^o)$

My textbook keeps telling me to do this
$$\sin 60^o = \sin(60^o+45^o)$$
But how is this happening I just can’t understand why we need to add the $45^o$

A:

This happens because $\sin 90^\circ = \sin 135^\circ$, i.e., $\sin 90^\circ = \cos 45^\circ$.
As a consequence, $-\sin \theta = \cos (\theta-45^\circ)$. Thus,
$$
\sin (60^\circ + 45^\circ) = \cos (-60^\circ + 45^\circ) = \cos (15^\circ) = \sin 15^\circ
$$

A:

Let $\alpha=60^{\circ}$ and $\beta=45^{\circ}$, $\therefore \alpha + \beta=75^{\circ}$.
Since $\sin(90^{\circ}+\theta)=\sin(90^{\circ}-\theta)$, then
\begin{equation}
\sin\alpha+\sin\beta = \sin75^{\circ}=\sin(45+15)=-\sin15=-\sin\alpha
\end{equation}
Therefore, $\sin\alpha+\sin\beta=-\sin\alpha$ and $\cos\alpha+\cos\beta=-\cos\alpha$.
According to properties of tangent circle, we can obtain
\begin{equation}
\tan\alpha+\tan\beta=\tan(45^{\circ}+15^{\circ})=\frac{\sin15}{1+\cos15}=-\frac{\sin\alpha}{\cos\alpha}=-\tan\alpha
\end{equation}

Q:

What is the proper context for chaining HTTP calls?

What is the preferred context to make a REST api call?
Say I have a service that returns a list of objects.
public class ExampleService
{
public List GetExampleData()
{

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